Re: simple(?) algebra question


"bob" <bob@xxxxxxxxxxx> wrote in message
news:eq20n6$ku7$1@xxxxxxxxxxxxxxxxxxxxxxxx
ok, you lost me at 'extract common factor of b on left side'

everything before and after that made sense....


Sorry..

You need to establish how many "b"s there are on the left hand side. You've
got x lots of "b"s plus one extra "b".

This can be written as ( x + 1 ) lots of b.

i.e. b times ( x + 1 ) = b ( x + 1 )

If that doesn't fully clarify, use numbers...

e.g. if you had 4 bananas plus 1 banana, that's the same as 5 bananas.

This can be written as ...

4b + b = ( 4 + 1 ) times b = 5b.

HTH, but if not (and being an education group) others here may be able to
explain more clearly...


--
Martin

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