Re: solving hyperbolic equations
- From: "~ßïtzChiçk~" <sheri.kurowski@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 02 Jan 2007 22:29:54 GMT
David W. Cantrell wrote:
"~ßïtzChiçk~" <sheri.kurowski@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote:Hang on a minute
I have the following equation to solve:
cosh^2(x) + sinh^2(x) = 0.2
Substituting with the identity cosh(2x) = 0.2 = 1/2(e^2x+e^-2x) and
forming a quadratic,
I end up with a quadratic equation with a discriminant less than
zero, which makes the solution a complex number
Where have I gone wrong?
You've gone wrong only in thinking that the solutions should not be
complex!
David
Do you mean the solution is a complex number?
I come up with e^2x = 0.2 + j0.98 and e^2x = 0.2 - j0.98
That can't be right because I don't know how to proceed from there
sheri
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