Re: phi and the divine proportion. Mathmatical thicko needs help with 1.618 and its use in art.

In article <HZauf.10313$W4.4511@xxxxxxxxxxxxxxxxxxxx>,
"Jay Kaner" <skinup@xxxxxxxx> wrote:

>Hi Group
>
>I've been trying to find out how to use phi in framing photographs. But so
>far I haven't been able to find anything that helps explain how to do this
>in a nice, easy way that i can understand.
>There's plenty of hits about all this on google but, like I said, none which
>was any help to me.
>
>To give you an example, I have a photo frame that is 4 X 6 inch. How would
>I find the phi/divine proportion 'point' of each side?

Firstly, the golden ratio is most often used in classical art and
architecture as the ASPECT RATIO of a rectangle. So maybe you should
crop your 4 by 6 photo to
(6 / phi) by 6.


>Would I be right/nearly right/nowhere near right in thinking a good rule of
>thumb for finding phi is to divide any length into 3 and phi will be two
>thirds along? So the phi point of a 6" length would be around the 4" point?

No. That gives you a ratio of 2:1 (i.e. 2/3 : 1/3).

>
>0 1" 2" 3" 4" 5" 6"
>|<----------------------|----------->|
> ^
> phi 'point'?
>
>So, waddaya reckon...fairly accurate way of doing it? Or not?
>
>I would be really grateful for any help in explaining the best way of doing
>this.
>
>I just ask that you don't use any of those (for me) brainachingly
>complicated looking mathmatical equations to explain what to do because, to
>be honest, they don't really mean much to me.
>I am, and I don't mind admitting this, a bit of a dimwit when it comes to
>maths. I don't mind the odd bit of adding/subtracting/timesing and dividing
>every now and again but I draw the line at equations
>
>That's why google wasn't much help.
>All the phi/golden ratio/divine proportion info was explained using those
>brainachingly complicated looking mathmatical equations.... and... Me +
>Equations X mathmatical incompetence = blank stares.
>
>So if somebody in here could give me a practical, easy to understand method
>for finding the phi 'point' in any given length I would be forever grateful.

For a line of length X, the point at X/(1 + phi) divides it into 2
segments that have the golden ratio. The proof of this fact involves an
equation, so I'll skip it.


>Cheers, and thanks in advance for any help you may generously chuck my way.
>
>J.

HTH.

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