Re: maths problem

On Mon, 21 Nov 2005 14:37:59 UTC, anw@xxxxxxxxxxxxxxxx (Dr A. N.
Walker) wrote:

> Any reason why you shouldn't solve for g(x) = 0 where g(x) = -1
> for x < x0, = f(x) for x >= x0?

That's effectively been what I've been doing, but the algorithms I
have been using don't like being in a place where g'(x) = 0: they
don't know which way to go. Better algorithms needed!

> Or something similar. Or for f(y) = 0
> where y = log (x-x0)?

I think the last is the likeliest candidate. Five hour train journey
coming up, laptop fully charged, Maple and C at the ready ...

Thanks,

Ian
.

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