Re: Do I need logarithms to solve this?

Fri, 21 Oct 2005 20:39:36 +0100 from ljs15
<djliam@xxxxxxxxxxxxxxxxxxxxx>:
> Right - I have the equation y = 2e^x+1, and I need to find x in terms of y.
> Am I heading along the right lines by taking the natural logarithm of each
> side, i.e:
>
> ln y = ln(2e^x) ln(2e^1)


"Take log of both sides", yes, but your right-hand side isn't
correct. First subtract the 1 from both sides:

y-1 = 2e^x

Then either divide by 2 and take log of both sides, or take log of
both sides and divide by 2:

ln(y-1) = ln*2) + x
ln(y-1) - ln(2) = x
or ln( (y-1)/2 ) = x

--
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
http://OakRoadSystems.com/
"You find yourself amusing, Blackadder."
"I try not to fly in the face of public opinion."
.

Relevant Pages

  • Changing Outlooks Look
    ... I want to divide it into 5 ... and give each column a heading. ... second appoinment shows up next to the first, I want to set it up to showup ... Is this possilbe? ...
    (microsoft.public.outlook)
  • Re: Do I need logarithms to solve this?
    ... > Am I heading along the right lines by taking the natural logarithm of each ... You are going to have to use logs, ... Prev by Date: ...
    (uk.education.maths)
  • Dividing a cell
    ... Is it possible to divide a cell so it will have two parts. ... This is required to label heading one part for horizantal ...
    (microsoft.public.excel.misc)