Re: Mathemagickal Dullskuggery

Oh No <notI@xxxxxxxxxxxxxxxxxxxxxxxxxxxx> writes

Well I have been around the circle once again, and I am essentially
back
where I started.

I hope its a spiral and not a circle.
With luck an upwards spiral.

The path of Pioneer is Newtonian, but because Pioneer
is to drift off into an expanding space, expansion must be taken into
account when it is regarded as an initial state for a quantum motion
from it to us. But since the fixed frame of the solar system, does not
expand, expansion is not present in wave motions in the solar system.

I don;t know why you are so sure that there is no fancescan doppler.
Nobody has dried to measure it within the solar system to a level of
accuracy (that is with other error sources suppressed) it would show ap
at.

I assume it DOES happen, but cannot be currently observed.

Despite protestations that this does not make sense, actually the only
thing which does not make sense is thinking that a photon is a wave
somehow present in a pre-existent space. This viewpoint does not make
sense even in standard quantum theory, and is understood by at least
those who adhere to the orthodox interpretations that the wave is just
mathemagickal dullskuggery. The only new feature is that the
dullskuggery works a little differently when expansion is required for
a
description of the path of the reference matter in the distant body.

I can't see this as a problem. Typically reference frames measure the
same thing differently. In fact, that's the whole point.

The other thing, which I did not take account of before, is that the
shift in Doppler is preserved in the relationship between quantum and
classical wave frequencies in the distant object, so that it is present

in two way as well as in one way Doppler measurements.

Hmmm....
You will have to be MUCH more clear.

Also I was putting down the shift to acceleration in time. Actually it
is down to the weird stretching of quantum coordinates, so that where
classically the expansion rate would be equal to Hubble, now it is half

hubble, so that the illusory acceleration is given by the difference,
i.e. by an inward acceleration of half hubble, which like the expansion

itself gets doubled up and appears as Hc.

I had assumed this is what you always meant.
Nothing else seemed to be consistent.

--
Oz
This post is worth absolutely nothing and is probably fallacious.



.

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