Re: Co-optation Today
- From: John Harshman <jharshman.diespamdie@xxxxxxxxxxx>
- Date: Wed, 09 Jan 2008 14:35:27 -0800
Rusty Sites wrote:
John Harshman wrote:Rusty Sites wrote:John Harshman wrote:A tree is just a graph. That graph can be interpreted as you like. I gave an example of a tree interpreted as a non-nested hierarchy. Now it's true that any rooted tree can be interpreted as only one nested hierarchy in which its terminal nodes, but not its internal nodes, are elements, but there is no a priori reason why you have to interpret the tree that way. To put it another way, every nested hierarchy implies a tree, but a tree doesn't imply anything; it's just a topological figure.r norman wrote:
In other words, every tree can be interpreted to be a nested
hierarchy. You have to do the same with phylogenetic trees. The
nesting requires that a node be associated not only with the species
that occupies that node but with the clade descended from that
species.
I agree. Every tree *can be interpreted* as a nested hierarchy. Or it could be interpreted as a non-nested hierarchy. That's why I say that a tree is a representation of the hierarchy, not the hierarchy itself. This is not a big deal. But a nested hierarchy is best understood and defined in terms of sets, not trees. And of course a natural nested hierarchy is best *explained* by a tree.
Well trees can be defined in terms of sets. From Donald Knuth
A finite set T of one or more nodes such that:
1. there is one specially designated node called the root of the tree, root(T); and
2. the remaining nodes (excluding the root) are partitioned into
m >= 0 disjoint sets T1, ..., Tm, and each of these sets in
turn is a tree. The trees T1, ..., Tm are called the subtrees
of the root.
I think this is properly called a rooted tree.
A rooted tree can be represented as
{a, {b, {c, d}}, {e, f}}
which is a nested hierarchy of sets. I don't see how it could be interpreted as a non-nested hierarchy.
I am not sure how you are using graph, but in the mathematical sense a tree is a special case of a graph. Every tree is a graph, but not every graph is a tree. In the most general definition of a tree, there is no specified root node, so there is not a one to one correspondence to a nested hierarchy. (At least, a root has to be specified to construct a nested hierarchy) A rooted tree (which is commonly what people think of when they speak of trees) does have a specified root so it avoids the problem. Your definition of nested hierarchy,
I agree that a nested hierarchy can be described using a rooted tree, and that each nested hierarchy corresponds to exactly one rooted tree. By "graph" I meant a figure composed of branches and nodes, each node connecting either 3 or more branches or being at the end of only one branch. In systematics, a tree is a graph in which there is one and only one path between any pair of nodes. A rooted tree is a tree in which a point on one of the branches has been designated the root node. Terminology in mathematics may be different.
Here: a nested hierarchy is a set of groups in which each group has one of two relationships with each other group; either the two groups are wholly disjunct, or one group is entirely included within the other. Partially overlapping groups are right out. Phylogenies can further be described as natural nested hierarchies: only one hierarchical arrangement of groups will work.
is, I believe entirely equivalent to the definition given for a rooted tree if a common ancestor of all members of the hierarchy is included. Otherwise, a nested hierarchy might contain no root node. It would then be a set of rooted trees. The groups in your definition translate to subtrees. Given two subtrees, they are either disjoint or one contains the other.
Well, in practice we never have a common ancestor. Instead we designate some particular branch as containing the root node, because of information extraneous to the tree itself. But a tree described as nested sets wouldn't seem to need an element identified as the ancestor. Why, mathematically, is a common ancestor needed? It would seem to be a superfluous member of the set, since the first division of the set defines a root.
.
- Follow-Ups:
- Re: Co-optation Today
- From: Rusty Sites
- Re: Co-optation Today
- References:
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: Treus
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: Charles Brenner
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: r norman
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: r norman
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: r norman
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: Rusty Sites
- Re: Co-optation Today
- From: John Harshman
- Re: Co-optation Today
- From: Rusty Sites
- Re: Co-optation Today
- Prev by Date: Re: Termite Nests in the Morrison?
- Next by Date: Re: How Our Brains Ignore Unpleasant Facts was: Re: The Reasonable
- Previous by thread: Re: Co-optation Today
- Next by thread: Re: Co-optation Today
- Index(es):
Relevant Pages
|