Re: Chez Watt: There can be no Evolution by natural selection DJT

On Nov 1, 10:14 pm, Christopher Denney <christopher.den...@xxxxxxxxx>
wrote:
On Nov 1, 8:40 pm, Ken Shackleton <ken.shackle...@xxxxxxx> wrote:

On Nov 1, 9:27 pm, Christopher Denney <christopher.den...@xxxxxxxxx>
wrote:

On Nov 1, 7:21 pm, Harry K <turnkey4...@xxxxxxxxxxx> wrote:

On Nov 1, 2:17 pm, Christopher Denney <christopher.den...@xxxxxxxxx>
wrote:

On Oct 29, 2:44 pm, Rusty Sites <SpameYou...@xxxxxxxxxx> wrote:

Christopher Denney wrote:
On Oct 28, 7:44 pm, Rusty Sites <SpameYou...@xxxxxxxxxx> wrote:

<massive snippage>

Yes, but the point was that adding air to the iceberg does not change
the amount of water is displaces.

Actually it does, the iceberg is bigger because of the trapped air,
than it would be if it had no trapped air.
The trapped air displaces ice that would otherwise occupy it's volume.
Thus the density of the iceberg is less than just ice. (i.e. it's
bigger for the same mass of ice)
Thus the amount of water, per unit mass, displaced is increased.
That means that for every unit of mass of ice, the iceberg with air
trapped will ride higher in the water ...

No. A floating object displaces its weight(mass) in the liquid. The
shape of a floating object has no effect on it's mass. The only way
the berg will displace more water is if you add mass to it amd adding
air at atmospheric pressure does not do that.

Harry K

Harry K

Nope, totally wrong. The displacement of an object that is negatively
or neutrally buoyant is wholly determined by its volume.

In this you are correct, an object can only displace the lesser of its
weight or its volume....if it runs out of volume before it runs out of
weight, it sinks, otherwise, it floats. If the two are equal, then it
is neutral.

The
positively buoyant things decrease their displacement, somewhat, by
having bits stick up above the level of the surface.

Huh? A positively bouyant object will *always* displace its *weight*
irrespective of its volume.

[snip]

That may be true of hollow objects (boats), but for relatively
uniform, solid, objects one uses their density to calculate
displacement.
Density is mass/volume, so volume is actually part of it, for ice
bergs, anyways.
The less dense the ice, the less the displacement for a given mass.
i.e. the less ice under water.

Aw carp and bones, I did it again.
This should've just read "The less dense the ice, the more mass is
above the water."
Nevermind, I just need to go to bed at this point.

.

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