Re: Ye Old Spacker Admits he's gay.

spintronic wrote:
On 8 Oct, 18:10, josephus <dogb...@xxxxxxxxxxxxx> wrote:



you give one equatio as f(a) = g(b) +h(c) +l(d)
then you return ds (2*PI/350) .... the solution is not
functionally related to the equation you gave us.

Never said it was. I said it was an equivalent expression, in that
it does the same job. It finds the distance ds on a sphere.

a ds is not on the sphere it is an abstrct value


The reason I ask this question, is to get you to do something
that does not involve (quoting formulas out of books).

So, let me simplify, to hold you down and stop you wriggling out of
this any further.

In laymans terms.
Find a beechball,

draw an equatorial line = x.
draw a longitude line = y.

Using only trig, find the shortest distance between any 2 points
x^2 + y^2 = z^2. Where z is the distance between the 2 points.

Can I possibly make this question any easier?



You obviously was not upto the challenge!

I can write gobbldegook that is configured like an equation but it
is not defined for example I can write prt(abcd/mnop) and say you
should know that function.


You can't use that as an excuse, I never asked you to solve the
equation.
I told you its function, and asked you to derive an "alternitive
expression"
from trig.

spin wrote for spinlandia
--I know, lets play a game.

--This is a formula for finding the square of
-- the distance (delta s)2 on a sphere.

-- (delta s)2 = (g_11 [delta x_1])2 + (g_12 [delta x_1] [delta x_2]) + (g_22 [delta x_2)2

--Find an equivalent equation that uses only trigonometry.


thre are several problems with this cryptic equation.

1 what kind of operator is delta? dx , or del

what kinds of implied objects are G_11, G_12 and G_22

let us assume this is a matrix expression where the entries are the discrimant of a matrix.let us say delta is a dx operator and the concatentate 2's are powers.

ds^2 = g[1,1]* d(x_1)^2 + g[1,2]* d(x_1)* d(x_2) + g[2,2]*d(x_2)^2

there is no consistent method associated with the subscript indexes. it is clearly an expression of those kinds of terms. but it it not clear what kind of physical function are we talking about. I assume X_1 and X_2 are variagls. the dx operator could ds/dt or ds/dr or some other relation.

this is an ambigous equaition without proper anticedents.

and you did say it was not related to the solution. this is a spinlandia trick where you give me gibberish and then ykou provide the "ANSWER"^tm


but i sometimes forget and my capitals are not not consistent.

I did not make up m= GMs/C^2 it was used extensively in all the
derivations for perihelion advance and other solutions. in fact how did
you calculate the advance to show I was right or wrong. if you did not.
you were being disengenous

the formula for advance for any planet == 6*m*pi/A(1-e^2)


I used

(delta varphi) approx (6 pi GM)/(c^2 A (1-e^2)) I even placed a pic
for you
when I explained how I derived it.


you cannot evaulate that expression with out knowing what m is.


Just did!
I know haw that equation was derived and I know how m was defined. your explaination is wrong.



M is defined in the same manner that AU is defined.
M is the unit distance in the field of all Black Holes.

You cannot use M = BH Mass, in V^2 = GM/r & GM/c^2 = m,
in one sentence and then redefine mid sentance as
M = 1476.62477, without explaining what the hell is going on.

I know its easy copying equations out of a book, but at least
the book lets you know whats coming up.
M= 1476.62477 = 1.3271244E20/299792845^2 m = GMS/c^2

I did not copy that value out of a book. I used a calculator. in
the book I have about relatavistic orbits they use ~~1.5km and expect
all calculations to be in km. I use meters.

if we know the avereage distance to some object and it is an orbit.
I can calculate its Period.

I have a complex K in my calculator it is gaussian^2/4*pi
and asuming ithe mass is very small I ignore masses.
A is in AU

(A^3/( k ))^2 = Period
A= 39.44
( A^3 = 6.134945638E4/K)^(1/2) = 90469.8 days for pluto
247.8 julian years

K = 7.495543799E-6


You didn't address WHY you changed the value of M (mid sentence).

what are yu talking about? I thought we were talking about
m = gM/c^2


GBH/(1/4 * Schwarzschild Radius) is not V^2.

If by V^2 you refer to orbital velocity, You are out by 4

If by V^2 you refer to escape velocity, You are out by sqrt(2).

You are always out!

thinking about what you are trying to say. you maintain that T is
realtive to escape rather than V you ned to justify that assertion.


Because it is! Which V? Do you mean?

that is proof by asserton not valid.
why is escape valid for time? it is a different function. GBH/m = the event horizon iself. nothing can orbit lower.

because I know the event horizon is wher everything fails. I looked at
the orbit of a mass in a minimum distance orbit. m shows up. I want
yuou to explain why 2v^2/c^2 that is a different quetion than qestion
of clocks and orbits. need to give me a referece for the eqatuion to
escape.

I dont have a reference I derived it myself.

then give me the derivation.

that does not make senxe in terms of GGH/m*c^2 =1 and you cannot
travel faster than light. so 2MGH/M*c is -1 not zero.


Arrrggghhhh, Now what is GG, and MGH?

you really are stupidly intolerant of typos. I am sorry but I was talking about 2*G*BH/c^2*m = -1 sorry I cant even see what I am typing since I type blind. so I often hit the other key.

I find you insecure and eager to complain.


you need to explain why the escape value is being used.
For ease of use!

explaination of proof by assertion. it is true because I say it is.

josephus

--
I go sailing in the Summer and
look at STARS in the Winter.
"Everybody is igernant, jist on differt subjects"
Will Rogers Jr.
"it aint what you know that gets you in trouble
it is what you know that aint so"
Josh Billings.

.

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