Re: trapping a comet in 1514 BC



On Jun 28, 9:31 pm, Elijahovah <rschil...@xxxxxxxxx> wrote:
The comet came from the direction of the sun having passed
perihelion it was slowing down as it comes toward Earth.
it got trapped by passing behind Earth path which is twilight
(6pm Egypt time) when the moon was at 1st quarter so that the swing
of the moon-Earth system curved the comet into a geosynchronis
orbit over the equator. The comet is therefore due south 30degrees
of zenith at all times, and only at full moon can its tail reflect
back
toward Earth.

Why not say that it passed near Jupiter which had a reverse slingshot
effect to slow the comet to little less than Earth's orbital velocity
around the Sun? Then as the comet approached Earth's orbit on the way
in or out it would be travelling at the right speed for capture.

This occurs at equinox, but cannot at soltice full
moons because the trajectory is not the short path to Sinai.
An ecliptic orbit would move north 23 degrees and south 23 degrees
(total 47 degrees), It would refect to the ground of Sinai only
on the midnite of winter solstice. But instead the orbit was
equatorial so that the refeltion was at both equinoxes at full moon.
The question is what size doe a comet have to be to have its
tail an atmospheric event 22,307 miles away.

A geosynchronous orbit would have the comet above one place on Earth
constantly and the Earth would pass through the tail everyday. A
comet's tail is huge but not dense. They are visible from tens of
millions of miles away, but from 22K miles, I think you would mostly
see the space in between the particles and the reflectance of the few
particles wouldn't register on the retina. The shooting stars from the
comet's debris would light the sky, day and night.

if you look at the seasons that are required for each plague
you will get the months they occurred, then if you look at
the 1st quarter moon of that month in 1514 bC you have your
date of comet encounter.

The particles that a comet sheds remain in the comet's orbital path
for years. When a comet's path crosses the Earth's orbital path, the
Earth will pass through it at the same time every year, so that there
are three nights of meteor showers. A comet that was slowed by Jupiter
might be slow enough to enter an orbit around the sun that crosses
Earth's orbit four times a year, then be expelled from the inner solar
system after its next encounter with Jupiter. This would make your
scenario a bit more plausible, but is better evidence for Roman
theology, by Jove.

By the way, impact by asteroid impacting the yucatan and
blowing dust up over wisconsin bringing down the water canopy
of 45 feet of fresh water changing earth's surface from 3x14.7 pounds
into 14.7 pounds occurred on Julian Nov 20 of 2370 BC at 4pm
tilting the axis from Canada to current pole.

Don't forget to calculate the temperature rise from lowering that much
matter to the surface of the Earth. The potential energy is
proportional to the mass of the water times the height of the canopy,
which is converted to kinetic energy as it falls, which is then
converted to heat. Also, the heat of condensation must be considered.
Think of how much heat it would take to vaporize that much water.
That's how much heat you get back when it condenses to a liquid.

The canopy took
47 days to collapse, and experience of 40 days in america
or 40 days in Iraq, 7 days to get there. All myths, all calendars,
all stronomy, verifies by corrections it ended on 2369 BC
Jan 6 Julian which is day KiahTse.

"Verifies by corrections" means they don't actually verify anything
until they have been fudged.

Mayan calendar is off
only 20 days, the unit they created.

If a meteorite large enough to kick debris from Mexico to Wisconsin
hit the Yucatan, there would be nothing but Mayan smithereens to mark
the calendar.

--
Greg G.

Being a veteran girl watcher, I recall trying to visualize how she
would look without her clothes. Nowadays, I try to visualize how she
would look without her tattoos.

.



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