Re: [OT] Q re Hawking radiation

"Bobby D. Bryant" <bdbryant@xxxxxxxxxxxxxxx> wrote in message
news:dll5m8$q1t$6@xxxxxxxxxxxxxxxxxxxxxxxx
> [I'm asking this here because I know there are people here who know
> the answers, and I can identify the kook responses more easily here
> than elsewhere.]
>
> I don't get the major premise of Hawking radiation. As I understand
> it, it results from the fact that particle-antiparticle pairs can
> spawn so that one lies within the event horizon and the other lies
> without; the former remains within the black hole but the other one
> carries mass/energy away, reducing the mass of the hole by that tiny
> amount.
>
> However, ISTM that nothing actually leaves the hole. The "inside"
> half of the pair stays inside, and the "outside" half stays outside?
> How does the hole itself lose mass?
>
> For that matter, why doesn't *gain* mass, since it now has a particle
> inside that it didn't have before?
>
> What am I missing?
>

The particle and anti-particle must appear EXTREMELY close to the event
horizon such that one is captured and the other is not.

The, let's say, anti-particle that falls into the black hole will eventually
interact with a particle and destroy each other leaving only energy behind
(mass conversion into energy).

Now the released partical-anti-particle energy MUST REMAIN in the black hole
(since not even light can escape. Does this energy have a gravitational
effect on other stuff? If not, then the net gravitational mass of the black
has decrease... the black hole has gotten smaller.

Hope this helps.

Dwib


.

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