Comparing proportions: same survey (for Hari)

From: "pierre" <pr.mullins@xxxxxxxxxxxxxx>
Date: 19 Sep 2005 19:40:30 -0700

Hi
I think what you want is in the paper by Scott and Seber (1983):
Comapring populations from the same survey.The American Statistician 37
(4), 319 - 320.

The formula you want (std err of diff) is:

se(p1 - p2) = sqrt((p1 + p2 - (p1 - p2)^2)/n)

Cheers
pierre

.

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