Re: permutation p value vs. normal p values
- From: Richard Ulrich <Rich.Ulrich@xxxxxxxxxxx>
- Date: Tue, 16 Aug 2005 14:28:05 -0400
On 16 Aug 2005 11:09:50 -0700, arrayprofile@xxxxxxxxx wrote:
> Hi, I am performing Cox proportional hazards regression on a microarray
> dataset with 15000 genes. The p values generated from the Cox
> regression based on normal distribution showed only 2 genes have a p
> value less than 0.05. However, I did a permutation on the dataset to
> obtained permutated p values, and it turned out about 750 genes had a
> permutated p value less than 0.05. With that big difference in the
> number of significant genes, which one should I trusted? and what's
> reason why such a big difference exists? My dataset is not large in
> sample size (17 samples), might this be the reason?
Having a data set with no-power for the test in
hand will result in having no 'significant' results.
For instance, you can't get a non-random selection
of head/tails if you looking at sets of 3 flips.
Off hand, I don't have any idea what you might be
using a Cox proportional hazards model for, with
microarray data. Where do you get a time-related
event, anyway? Were you creating dichotomies from
each array item, and looking at some survivorship time?
Having 750 p-values at 5% or less, out of 15000 tests,
is exactly the number expected by chance. Is this, indeed,
the actual number, and not a mis-reading?
-- "permutions" takes the extreme 5% of results as a marker,
or cutoff. If there was exactly no-effect, the permutation cutoff
would also cutoff 5% of the sample, or 750 plus or minus 55
or so. I'm wondering if this is coincidence, or if you might be
looking at the wrong numbers, somewhere.
--
Rich Ulrich, wpilib@xxxxxxxx
http://www.pitt.edu/~wpilib/index.html
.
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