Re: My Fusion Engine

I removed the plastic box and the reverse power came back after the ionised
gas got hot as before.

Well that was a waste of £50 (GBP)!

My shrink called today and I gave a demonstration however the shrink and her
beefy assistant had no understanding of radio or physics. I refused
"treatment" and they went away. I told them not to come back and to
discharge me back to my GP.



--
Chris.
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"Chris" <ns_cjrs@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:gRAkl.34037$715.14222@xxxxxxxxxxxxxxxx
I put a plastic box over the capacitor to protect me from high voltage and
tried the experiment again. This time there was no reverse power after
adjusted to zero and it did not rise as it did before.

This time my report is for zero output after the ionised gas got hot.

--
Chris.
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"Chris" <ns_cjrs@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:MHekl.28481$nx.23089@xxxxxxxxxxxxxxxx
I have been using a linear coil for my experiments.These experiments are
suspended. I've now requested a pyrex toriod to wind a coil on and see how
the plasma behaves.

I am expecting more power from this as the ionised gas cannnot spew out
of the end and the whole circle tube near the centre line will be the
active region.

That means that not so much power will be lost and so the plasma will get
hotter and since the active region is bigger then more power will be
developed.

Chris.
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Chris.
"Chris" <ns_cjrs@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:uiKjl.15978$j64.11115@xxxxxxxxxxxxxxxx
I made a mistake that partially cancelled:


In fact the ionised gas shows a series resistance that decreases the
dynamic impedance that creates a small mismatch. If the gas conducts
better this reduces the extra series resistance and will increase the
dynamic resistance, making this smaller or zero will not change the
dynamic resistance as the effective series resistance approaches its
value that it was without the tube. The only way the dynamic resistance
can increase is if the effective series resistance decreases and this
can only occur if the plasma resistance goes negative meaning that power
is being produced and this can only come from fusion in the gas.

The mismatch was a VSWR of 1.2 with Forward Power=100 and reverse power
= 2

(VSWR-1)/(VSWR+1)=(ZL-ZS)/(ZL+ZS)

0.2/2.2 = (Z-50)/(50+Z)

0.167*(50+ZS)=Z-50

8.35 +50 + 0.167 Z=Z

58.35=Z*0.833

Z=69.62 OHMS

Since the turns ratio is 15:1 the impedance ratio is 225:1 so the
impedance of the tank circuit for the input impedance of 50 ohms is
11250 but for the state where the reverse power is 2 watt then the
impedance of the 15664.5

Rd=L/Cr =2.3E-6/8E-10r=2875/r

with the input impedance of 59 ohms r=2875/15664.5 = 0.18 ohms when the
input impedance is 50 ohms r=0.26 ohms so the resistance of the plasma
is 0.18-.26 = - 0.08 so the plasma has a negative resistance of 0.08
ohms so 2 watt of fusion is going on.

This represents burning1E-10 g of hydrogen per second.




"Chris" <ns_cjrs@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:9kJjl.23584$Nn6.6422@xxxxxxxxxxxxxxxx

If my theory is correct the power can only come from fusion. The fusion
reaction is so powerful that 2 watt is only 3E-9 grammes of hydrogen
burned per second in a fusion raction.

Chris.

"Chris" <ns_cjrs@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:n3Jjl.33437$jz5.19548@xxxxxxxxxxxxxxxx

In fact the ionised gas shows a series resistance that decreases the
dynamic impedance that creates a small mismatch. If the gas conducts
better this reduces the extra series resistance and will increase the
dynamic resistance, making this smaller or zero will not change the
dynamic resistance as the effective series resistance approaches its
value that it was without the tube. The only way the dynamic
resistance can increase is if the effective series resistance
decreases and this can only occur if the plasma resistance goes
negative meaning that power is being produced and this can only come
from fusion in the gas.

The mismatch was a VSWR of 1.2 with Forward Power=100 and reverse
power = 2

so RP/FP= 0.2

so reflection coefficient = 0.2 = (ZL-ZS)/(ZL+ZS) = 0.2= (50-Z)/(50+Z)



0.2 *50+ 0.2 * Z = 50-Z so 10-50 = -Z-0.2*Z

so -40=-Z(1.2) so Z = 33.3 ohms.

L/Cr=RD = 11250 and RD = 7492.5

L=2.5 x 10^-6 C=7.39x10^-10

2.5E-6/r=11250 = 3383/r r=11250/3383=3.3 ohms

r with 2 watt reverse power = 7492.5/3383=2.2 ohms

so the plasma showed a negative resistance of 1.1 ohms.

Since Power = I^2*R then the extra current this power of 2 watt
generated by the 1.1 ohm was 1.3 amp.

"Chris" <ns_cjrs@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:tSAjl.14454$Ci3.8127@xxxxxxxxxxxxxxxx
The Fusion engine that I am trying to make will be found not to work
as this protect the income of those who get incomes from petrol,
coal, oil and windmills. This is because their prosperity depends on
it. These people are known as the "Establishment" and include the
Royal family, the aristocracy, the nobility, the priesthood and
lawyers.

If I make it work I will be executed to protect these incomes. Others
have already died. A member of this tribe has told me the truth and I
have been told this more than once.


100 watts to excite the discharge and I'm getting 2 watt back. This
is due to a drop in the resistance of the gas as it heats up. Some of
this change may be due to fusion causing the same effect as negative
resistance. The dial reading is an indication of the amplitude of the
oscillations in the tuned circuit. This one is tuned to 3.7 MHz.

http://www.chrisspages.co.uk
Chris













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