Re: physical principle responsible for EMwave propagation

On Sun, 15 Jul 2007 15:28:26 -0700, srp@xxxxxxxxxxxx wrote:

On 15 juil, 17:49, John C. Polasek <jpola...@xxxxxxxxxx> wrote:
On Sun, 15 Jul 2007 07:55:06 -0700, s...@xxxxxxxxxxxx wrote:
On 12 juil, 08:31, Rudolf Drabek <newsr...@xxxxxx> wrote:
This is no joke, I ask for help.

Maxwell's theory is wellknown and describes all the math.
relationships of EM waves.
To date I never had the idea to ask for the physical principle behind.

I know and accept the induction principles that charges are the cause
for EM fields.
The vacuum has c, e_o and my_o, but where are the propagating charges?

Would be nice to get really a serious answer of my request.

By definition e_0 (eps_0) is a unit of capacitance per meter of
vacuum and mu_0 is a unit of inductance per meter of vacuum

Both of these are associated when full treatment of em
waves is done. The Poynting vector is a reflection of this
association.

Capacitance implies displacement current, which in turn
implies charges. But it is true that in wave treatment,
there seems to be no traces of charges being associated.

On the other hand, it is known since Planck that light
does not really propagate as a wave despite the usefulness
of wave treatment, but as quantized quantities (photons)

Presumably, when the internal dynamic structure
of individual photons is better understood, we may
finally discover the apparently missing charges.

André Michaud

I have the impression that all light comes from quantized transitions
in the atom, so that each such transition is possessed of some exact
energy E = h*nu = h*c/L? It thereupon transmits as a wave in
pair-space or equivalent with wavelength L.

A close analog is dropping a pebble that has energy E = mgh into a
tranquil pond and watching that energy radiate as waves.It seems clear
the waves must possess energy E, but idt would be a stretch to claim
that E travels as a photonlike particle, just because it's quantized.

Would it ?

If the energy of a single photon emitted by one atom really did
radiated as waves, it would of necessity stop to be localized
and its energy would obviously spread out somehow, no ?

Since you subscribe to the SI system (from your book) you must endorse
eps0 and mu0 and therefore a transmission medium with speed c. I htink
we can both agree that it is not possible to suddenly introduce a
quantum of energy either into the water or the medium without some
natural reaction, which is the formation of radial waves in either the
2D or 3D case.

The energy is merely a bookkeeping entry whose value was last known
when the electron changed levels, but must now be accounted in the
departing wave, measurable only with difficulty.

The initial event is a minute flash of light, the wave front spreading
at c with a coherence such that at any point, with a suitable lens it
can be recovered and reproduced as a point image. The same cannot be
said of a photon.

So what I'm saying is the the event is a quantum event, and its
continuation becomes a continuum, but with a clearly quantized value.
John Polasek

Any absorbtion of such a spread out photon would involve
instant regrouping of all of that energy at the single localized
point of absorption (an electron that would jump to an orbital
further away from its nucleus).

This regrouping would instantly violate the speed of light as
a maximum velocity of energy, it seems to me, if the
spreading even slightly exceeds initial localization.

It seems to me that this does set some limit to such
spredding out. that limit being the speed required for
final regrouping, that is the speed of light, no ?

André Michaud

The missing charges are the virtual pairs in pair-space.
John Polasek

.

Relevant Pages

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