Re: Electrostatic Field Question
- From: chuck <nospam@xxxxxxxxxx>
- Date: Tue, 04 Jul 2006 10:24:45 -0400
chuck wrote:
My question has to do with actual measurements of a homogeneous electrostatic field of E V/m in air.
Sorry. I left out my assumption that E= 1 V/m.
.
A voltage is observed between two parallel plates in the field. Assume the capacitance of these plates is 1 pF and their separation is 0.1 m. I expect the voltage to be 0.1V.
A very high impedance electrometer will indicate this voltage, but presumably, a 10 Mohm DMM will not due to excessive loading. While this idea appears often, the only numbers usually presented are the 10(12) ohm input impedance of the electrometer and the 10(7) ohm input impedance of the DMM.
My question is this: how do I determine the "internal resistance" of the two plates in the electric field? How can I know the quantitative effect of different voltmeter loadings on the measurement (other than "less loading is obviously better")?
Knowing the charge on the plates, it seems that the DMM will discharge the capacitor in microseconds. What is the time rate at which the electric field replenishes the charge on the plates?
Thanks for any help or suggestions.
Chuck
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