Re: Lux with plain reflector?
- From: Thomas Paterson <t_p_paterson@xxxxxxxxxxx>
- Date: Thu, 18 Oct 2007 14:09:54 -0000
On Oct 17, 2:02 pm, "I.N. Galidakis" <morph...@xxxxxxxxxxxx> wrote:
I suspect this is fairly basic question for lighting engineers, but in my mind
it has not been completely cleared.
Suppose that in a certain arrangement with a lamp under a dark opaque ceiling
the illuminance below (on say the reading surface [X]) is measured to be 100
lux.
--------- ceiling
[L]
\
\
\
\
\
\
--------[X] table
What would the reading be if the ceiling is replaced by a perfectly reflecting
mirror? Would it be roughly double (i.e. 200 lux at [X])?
Assuming an omnidirectional source of zero size, it would be just a
tiny fraction under 200 lux (for theoretical purposes, call it
exactly). Do this as a thought experiment. The mirror is doubling
the universe, effectively creating a second light source above the
first. The reason it would be a fraction down is that the source in
the second universe is a tiny bit further away - double the distance
between the light source and the mirror, so in a theoretical universe,
you could make that zero. The real light source would also create a
shadow from the virtual source, hence the need to consider it of zero
size. In the real world, mirrors also suck some small amount of
light.
Rick brought up the difference between radiosity calcs and raytrace
calcs. He's right, to the extent that radiosity software generally
models reflected light as being of lambertian distribution (jump in
guys if I'm wrong on this one!) but it is possible, if you're clever,
to model a mirror in a radiosity model by creating a second space,
mirroring the first, then directionality works.
Thought experiments are usually easier than calcs, and for extremely
simplified, unnatural circumstances, the assumptions made by
raytracers or radiosity software will cause inaccuracies, not improve
the accuracy in general.
Regards,
Thomas Paterson
http://www.luxpopuli.com
.
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