Re: Material flow rate to power required.
- From: "SandeepSubrati" <sandeepsubrati@xxxxxxxxxxx>
- Date: 6 Aug 2006 03:42:46 -0700
Jerry Avins wrote:
SandeepSubrati wrote:
How to convert bulk material flow rate available in kg per second
(kg/sec) to power required at its driving shaft (of some big drum like
pulley)?
Consider that the angle while conveying is an average of theta degrees.
You need to know the distance that the material is raised. If it's
falling out of a hopper, no power is needed.
Jerry
--
Engineering is the art of making what you want from things you can get.
¯
CONSIDER A DISTANCE OF L METRES FOR THE MATERIAL TO BE RAISED AT
ANGLE THETA. BELT SPEED IS UNIFORM AT V METRES/SECOND.
.
- Follow-Ups:
- Re: Material flow rate to power required.
- From: Herman Family
- Re: Material flow rate to power required.
- From: Jerry Avins
- Re: Material flow rate to power required.
- References:
- Material flow rate to power required.
- From: SandeepSubrati
- Re: Material flow rate to power required.
- From: Jerry Avins
- Material flow rate to power required.
- Prev by Date: ladder editor and ansi c compiler
- Next by Date: Re: Material flow rate to power required.
- Previous by thread: Re: Material flow rate to power required.
- Next by thread: Re: Material flow rate to power required.
- Index(es):
Relevant Pages
|
Loading