Re: question for Ricky

Prichard,

"R" <rgere70_4@xxxxxxx> wrote in message
news:1140024145.587668.164930@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
The force vectors change from -, + , because of the angle of cos,
cos(0) = 1
cos(180) = -1, cos(360) = 1, it has nothing to do with m^2r being neg,
like your trying to prove, you sir are an idiot.

Your right I just have no clue, snickers


I AM right. You clearly *DON'T* have a clue. I'm not even sure that you
were able to completely read my post. It would appear NOT.

"m^2r" does not appear anywhere. I know.. I know... nasty TYPO.. eh? All
of your mistakes are just "nasty typos".

Secondly, as was clearly stated in my post (and every physics text in
print), the acceleration vector necessary to generate circular motion ALWAYS
points toward the center of the circular motion. ALWAYS. Can't fail.
Can't be any other way. Your concept about "removing the centrifugal *and*
centripetal* acceleration/force" simultaneously was seriously laughable.

And I still just LOVE the way that you think you can freely and arbitrarily
"MOVE" the mass of the piston to the crank pin... just because they happen
to be in the same engine. No math required..... just take the mass of the
piston and slap it on the crank pin! Brilliant! And then say that it
creates "centrifugal force"..... and just ignore the fact that it doesn't
really go around in a circle. Brilliant again! But I have to wonder why
you didn't also move the ENTIRE mass of the con-rod to the crank pin too. I
mean, after all... it's connected and everything....???! Doesn't it count?
Doesn't it accelerate? Doesn't it generate an imbalance force?

Hmmmmm........

The day's not even half done and you're already in the tank.

Giz




.

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