Re: On the World Cup format

On Feb 1, 8:16 am, Luke Curtis <tlot...@xxxxxxxxxxxxxxxxxxxx> wrote:

There are 14 teams in this world cup, raise it to 16 teams, have 4
groups of 4, 3 games for each team over the space of 2 weeks, top 2 go
through from each group then quarter,  semi and final over the next 2
weeks - simple.

No, reduce it to 12 teams. Three groups of 4, three games for each
over the space of 5 days.

Top two from each group form a single pool of six teams, ranked
according to group-stage results (points and net run rate). Then play
a Double Elimination series - that is, lose twice and you are out.
The games would be 1 v 2, 3 v 4, 5 v 6. After each game, a winner
moves up one game slot and a loser moves down one game slot, and they
play again. If the elimination of a team leaves an odd number, then
the top-ranked team gets a day off. Eventually there will be two
teams left, and their game is the Final.

So here's an example. After the group stages, the six qualifiers in
order are AUS, ENG, IND, PAK, RSA and SLK.

First round: AUS v ENG, IND v PAK, RSA v SLK. Results go with
seeding, so IND moves up one, ENG moves down one, RSA moves up one,
PAK moves down one.

Second round: AUS v IND, ENG v RSA, PAK v SLK. Note that the third
game there is a matchup of two losers, so one of them must be
eliminated at this point. From the second game, ENG could be
elliminated; but let's assume that the results go to seeding again.
SLK having lost twice are eliminated but five teams are left.

Third round: AUS bye, ENG v IND, PAK v RSA. All those teams have
lost once, so both games are eliminators.

Fourth round: AUS bye, ENG v PAK. Loser of that game, again, will
have lost twice.

Final: AUS v ENG.

In any permutation of results, the Second Round always has one
elimination game and the Third Round has either one or two
eliminations, because losses move teams lower in the draw.

The whole tournament - group stages and elimination rounds - takes
about 20 days.

JPD
.

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