Re: wave polarisation


"Richard Clark" <kb7qhc@xxxxxxxxxxx> wrote news:v85h055bb1upstfm20kf0tmh66nfjrvmsf@xxxxxxxxxx
On Mon, 11 May 2009 19:21:32 +0200, Szczepan Bia?ek <sz.bialek@xxxxx>
wrote:


Now we know that
electrons have mass and are compressible.

Nonsense.

Millikan measured it in XIX centuary. Latelly Wim wrote: "Hello Szczepan,

You are right, charge is compressible. The charge that is required to
charge (for example) a sphere seems to break the coninuity equition as
is used for incompressible fluid in hydraulics".

So at the ends appear and
disappear the huge charges. In that case an electric impulse is send when
the current flows to (from one end) , and the next when the current flows
fro (from the other end).

Nonsense.

I was told that the electrons want to escape from the ends of a dipole ( balls are a remedy).

So in one EM cycle are the two electric cycles.

Nonsense.

So the frequency is not doubled. The electric is twice more.

This is either very poor English, or more nonsense.

Let assume that something is radiated from the end when the charge (compressed electrons) appears. There are the two ends. How many pulses will be send in space ?

Does your measurements distinguish radiation from the spakrks from that from
the plates?
S*

Of course they do. More the question: can you measure them too?

No. The only instrument I have is the comb. But it was enough to verify the second meaning of word "polarisation". Everywhere is written that a charged comb attract a stream of water. And that it is caused by polarisation.
It is caused by electrostriction. Decreasing E-field deform water stream. Of course the electrostriction is caused by the polarisation of H2O particles. Charged comb do not attract water drops.

If you cannot, then this explains the nonsense.

Something is radiated from the ends of the dipole. Can you detect it?
S*

.

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