Chapter 19A from "Reflections III" - Step 13 response
- From: Richard Clark <kb7qhc@xxxxxxxxxxx>
- Date: Sat, 21 Jun 2008 14:55:39 -0700
Step 13.
It is thus evident that the amplifier has returned to delivering the
original power, 100 watts into the previously mismatched
complex-impedance load, now conjugately matched, the same as when it
was delivering 100 watts into the 50-ohm non-reactive load. But the
reflected power, 30.6 watts, remains in the coax, adding to the 100
watts delivered by the amplifier to establish the 130.6 watts of
forward power, proving that it does not enter the amplifier to
dissipate and heat the network or the tube.
Points in response:
1. The power accounting is wholly lacking in accuracy implications as
previously noted.
2. That 30.6W remains in the coax has been through the intervention
of the amplifier operator's tuning. The reflection of power from the
original mismatch clearly impacted the dissipation of the finals
without such intervention. Intervention was a necessity of preventing
the untoward, catastrophic failure of the amplifier (in a general
sense for all possible load reflection angles).
3. The 30.6W remaining in the coax is a function of tuning that cast
the issues of dissipation out of the tube, and moved the line of
dissipation towards the load (actually, into the tuning elements of
the plate and the line itself). This is the whole raison d'etre of
tuning the grid/plate or matching the load.
73's
Richard Clark, KB7QHC
.
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