Re: Superposition


"Richard Clark" <kb7qhc@xxxxxxxxxxx> wrote in message
news:viovj3l2v8cebon96vpdqaom99nb2l7fh6@xxxxxxxxxx
On Sun, 18 Nov 2007 00:16:47 -0500, "Stefan Wolfe"
<dbrocolli@xxxxxxxxxxx> wrote:

Let's rewind up that list of charades to revisit:
Well, power is a vector quanity subject to the rules of vector
math.
and ponder the implication of a negative power, for simplicity:
P1 = 50W @ 90deg
P2 = 50W @ 270deg
what does the math reveal?

I am not trying to define power as negative with respect to zero
Negative with respect to zero? What about with respect to positive?
Or even a smaller negative! How about half negative (only 90 degrees
shift instead of 180)?
What happened to:
Well, power is a vector quanity subject to the rules of vector
math.

I was so wanting to see your solution, much less how:
Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A)
migrated into the negated sine in:
= (50 - 0) + (50 - 0) - 2SQRT P1*P2 sine(A)


Oh God this is getting frustrating!

http://math2.org/math/integrals/more/restrig.htm

1. See top equation. THE INTEGRAL OF A COSINE IS A SINE. I added a minus
sign, I shouldn't have BUT IT DOESN'T MATTER. You add the minus when
integrating sine function to cosine...so it has been 40 years since my last
calc quiz...big deal, it makes NO difference in this integration problem.

2. P1(t) = P2(t) = 50, Ptotal(t) = 100

3. The integral of ANY sine wave from t=0 to ANY integral number of complete
cycles (2*pi radians) is ZERO. The areas on the top of the upper values are
negated by the areas of the lower sine values with respect to the reference
point.
The areas add up to ZERO. Remember? AGREE???

4. The power Ptotal(t) is expressed as the sum of P1(t) and P2(t) + the
cosine function (the angle are multipliers are not important because the
energy in the cosine function cancels out to zero). Thus Energy = 50(1sec) +
50(1sec)
+ K*(sine function) = 100 where K*0=0 over any number of complete cycles.

100 - source energy = 0. Energy is conserved. AGREE??

IF, and I repeat IF you EVER had any fundamental, formal education beyond
algebra I would like to know. This is so simple, I remembered it after 40
years as if it were arithmetic.

And where do you call "integrating" an equation "migrating"? Is that some
new mathematical function as yet undiscovered 40 years ago? Sir, I am using
the "Integral" function...can you please post references to the richard
clark "Migrate" function?

I never expected such a trove of mistakes cascading through successive
replies. This is a troll, right?

I think you are marginalizing your credibility with each succeeding post in
which you dispute freshman caluclus fundamentals. Depending upon your
education base, this could be quite a blow to you. I thought you knew
math...maybe it was just me getting the wrong impression. Are you pulling
our legs?


.

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