Re: Puzzle with five coins
- From: Philippe 92 <nospam@xxxxxxxxxxxx>
- Date: Mon, 12 Sep 2005 00:56:28 +0200
Ashok wrote :
In article <mn.558e7d592848b356.22155@xxxxxxxxxxxx>, nospam@xxxxxxxxxxxx says...
For the 7 cigarettes problem the picture is here : http://cjoint.com/?iAadlGRabe
Valid if Length > 6.0622 Diameter
Regards.
-- philippe mail : chephip at free dot fr site : http://chephip.free.fr/
Thanks, Philippe. How does the number 6.0622 come about?
I copy an article from Bob Pease (in Electronic Design Apr 97) :
The angle alpha = OMx is arc tan (2/sqrt(3)) = 49.1066° with O = center of vertical cigarette, M = nearest midpoint of one horizontal cigarette, with axis = Mx.
Then solve for L with the law of sines L/sin 60° =3D*sqrt(3) / sin(120° - 2 alpha) [...] then end with L/D = (7/2) * sqrt(3)
I admit that I didn't studied this proof thoroughly !
Ashok
PS: Any chance of an English version of your web site? :)
That would be fine ... As I'm changing the architecture of my site (because two much files in the same directory) I'll think for a general architecture allowing a full bilingual site Then just wait until I translate everything... (up to now, there are only just a few bilingual or english pages)
Regards.
-- philippe mail : chephip at free dot fr site : http://chephip.free.fr/
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