Re: Bayer filter removal
- From: Ilya Zakharevich <nospam-abuse@xxxxxxxxx>
- Date: Mon, 16 Apr 2007 11:51:27 +0000 (UTC)
[A complimentary Cc of this posting was sent to
ASAAR
<caught@xxxxxx>], who wrote in article <pir523dn2lkd71hn0i9u5n00edp94lr70u@xxxxxxx>:
Charles Schuler posted an informative link in this thread a couple
of days ago that may clarify the amount of attenuation that takes
place if the Bayer Filter Transmission vs. Quantum Efficiency chart
(Figure 4) is a fair representation. It shows fairly broad filters
with a good deal of overlap, and quantum efficiencies at different
frequencies ranging from about 8% to 38%, maybe averaging a little
bit more than 20%.
If you mean
http://micro.magnet.fsu.edu/primer/digitalimaging/cmosimagesensors.html
I do not see any QE spectral data on Figure 4. So what do you mean?
To find the effect of removing of Bayer, one needs to average these
curves with the coefficient given by the QE curve (well, it must take
into account the IR filter too). In principle, one could try to guess
the QE curve by dividing the "throughput" measured QE of
IRF+Bayer+Sensor by the data for the Bayer.
[Do not have the link for the measured QE at hand, but it was you who
gave it to me. ;-]
Hope this helps,
Ilya
P.S. Let me reiterate that my estimates of "throughput" QE of a 2005's
Canon's sensor (with sunlit scenes) were about 14%.
.
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