Re: Camber Thrust, Conning, and Out Riding

Timberwoof wrote:

Is that missing a term? How do you calculate that?

He's too brief, but correct.

L sin theta = 2 * sin 60 = 1.732

I will describe the force diagram in "Flight Theory for Pilots".

Draw two lines crossing at 90 degrees and center your imaginary aircraft on
the crosspoint.

The vertical line is *effective lift* going straight up, opposing the
aircraft's *weight* going straight down towards the center of the Earth.

The horizontal line is the plane in which the aircraft is turning.

The wings and fuselage have to generate enough effective lift to keep the
aircraft from losing while turning.

Draw a line passing the thru the center of the cross at whatever angle you
want to represent the bank angle.

Angle theta represents the bank angle from the horizontal.

A line drawn at 90 degrees to the bank angle of the wings has centrifugal
force pointed downwards at an angle and centipetal force pointed upwards at
an angle.

Total lift is in the centripetal direction. The wings need to generate total
lift to
turn at a banked angle.

cos theta = effective lift / total lift = W / L

The load factor on the airframe, G = L / W

G is a dimensionless number, not the same as g, the acceleration of gravity.

G = 1 / cosine theta

The centripetal force = L sin theta

Theta = arc cosine ( 1 / G )

--
Message posted via http://www.motorcyclekb.com

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