Re: McGuigan Series # ??

On 3 Mar 2006 19:51:31 -0800, "Mef" <mwillerth@xxxxxxxxx> wrote:

I find this description of the situation bizarre. B's grou0p is not
weak. W's stones on the outside are weak. B has one strong group
splitting two weak W groups.

Ah, then I see we've found the root of our problem, as you get stronger
and your positional analysis improves, so will your understanding of
why the correct answer is correct.

Let's ask any pros who might be reading this if they'd rather play
against a strong amateur with four corners that look like this:

.. . . . . . . .
.. . . . . . . .
.. . . . . . . .
.. . . X . . . .
.. . . . . . . .
.. . . . . . . .
.. . . . . . . .

or like this:

.. . . X . . . .
.. O O X O . . .
.. O X X O . . .
X X X X . . . .
.. O O . . . . .
.. . . . . . . .
.. . . . . . . .

If W can't enclose B -- and he can't -- how is the latter better for W
than the former?

-- Roy L
.

Relevant Pages

  • Re: McGuigan Series # ??
    ... W's stones on the outside are weak. ... splitting two weak W groups. ... Ah, then I see we've found the root of our problem, as you get stronger ... so will your understanding of ...
    (rec.games.go)
  • Re: Does anybody know ...?
    ... One thing I've noticed, in all the splitting ... The reason this works is the "Primitive Element Theorem", ... with the fact that splitting fields are normal extension. ... any irreducible polynomial over Q that has a root in F ...
    (sci.math)
  • Re: Does anybody know ...?
    ... One thing I've noticed, in all the splitting ... The reason this works is the "Primitive Element Theorem", ... with the fact that splitting fields are normal extension. ... any irreducible polynomial over Q that has a root in F ...
    (sci.math)
  • Re: Does anybody know ...?
    ... One thing I've noticed, in all the splitting ... field extension which is a divisor of n!, and certainly it is not hard ... field of fand therefore such that every root of gis contained ... polynomials with a root in this extension must split completely in ...
    (sci.math)
  • Re: McGuigan Series # ??
    ... splitting two weak W groups. ... Mef: ... and your positional analysis improves, so will your understanding of why ... by removing pairs of stones. ...
    (rec.games.go)