Re: Absurd schizo math vs 'reality'
- From: "eleaticus" <eleaticus@xxxxxxxxxxxxx>
- Date: Thu, 17 Aug 2006 19:15:50 -0500
"
It was Rich, I think, who brought up the word 'even' when mentioning
integers (for sampling, I reckon) in this two-envelopes puzzle.
But it would have to be not just even numbers, but multiples of four, to not
provide useful information, even given that the range of possible values for
the 'anchor' quantity did not include pain-inducement for the envelope
profferer.
But consider the sampling from all positive integers, with the second value
1/2 half the time, and doubled half the time.
Fifty percent of such samples would be odd, so one quarter of the resulting
values would be in half-dollars, 1/2 odd, 1/4 even (the doubled amount).
Almost fifty percent would be even and divisible by four so all of the
resulting values would be even.
The balance would be evens not divisible by four, primes times two, so one
quarter of the resulting values would be odd, and 3/4s even.
So,
1/8 would be half-dollars,
A little more than 1/4, odd.
Almost 5/8, even.
No problem if the envelope amount is not even: you must switch. That is more
than 3/8s of the total opportunities.
Tree-eighths of the almost 5/8 of the even amounts are greater than what is
in the second envelope. The odds are a little in favor of the switch.
This was the all-positive integers result.
Consider sampling from the evens only.
Because some of the evens are primes times two, the half-values are in these
cases odd, and less than half of the time an even value is not greater than
the amount in the second envelope."
--
(c) eleaticus
ee-lee-AT-i-cus
http://eleaticus.blog-city.com
"Edward" <edwardr121453@xxxxxxx> wrote in message
news:1155857089.660101.19490@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
must
eleaticus wrote:
I demonstrated previously in a post that in one scenario a switch was a
determiningin some/many circumstances without knowing the range.
Really? Can you post that again?
The selection process by the profferer, and his/her method of
the second envelope is more important than the range of 'possibles'.
But you aren't given that information. You can't make things up as you
go along.
Can you just read the details presented and give us the answer?
There are two envelopes in front of you. One contains twice as much
money as the other. You choose an envelope and it contains $10. You
are now given the option to switch envelopes.
Do you switch? Explain
Please, for the sake of all of us that don't really know, give us, in
one post, the answer and explain why your answer is correct.
.
- References:
- Re: Absurd schizo math vs 'reality'
- From: eleaticus
- Re: Absurd schizo math vs 'reality'
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- Re: Absurd schizo math vs 'reality'
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- Re: Absurd schizo math vs 'reality'
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- Re: Absurd schizo math vs 'reality'
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- Re: Absurd schizo math vs 'reality'
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- Re: Absurd schizo math vs 'reality'
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