Re: JokerStars is freaking rigged.

In article <pa74a3x5tj.ln2@xxxxxxxxxxxxx>, razzo@xxxxxxxxx
says...
> Nice expression, but it doesn't even come close to applying here. No where
> does 11 out of 12 AA lose.

Yeh, right.
I calculated using "AA wins 25% of the time at a full table if
nobody folds"
Let's say it really wins 50% [1] of the time, so it's
equivalent to a coin flip. Your claim above is the same as
saying that no set of 12 coin flips _ever_ will have 11 heads
in it.
Get a grip, dude!


[1] Since you've claimed it can _never_ happen, the actual
figure is irrelevant. p*(1-p)^11 is always >0, as long as p
isn't 0 or 1. Which it isn't, as I know from experience.
--
If I'd known I'd live this long, I'd have taken better care of
myself.
.

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