Re: Testing number due theory

basicstrategy777 wrote:
Gregg

Thax for taking the time to do that.

It appears that in a majority of the series ( column 1, specifically,
non-7 series 10 thru 26) the percent of times the next number was a 7
(last column) was greater than the probability average of 16.6; this
occured without a break for 16 series. It appears the 7 appeared more
often than it should have 16 straight times. The percentage
difference was approximately 6% in my favor.

Let us look at the 19th roll. If you took your bets off on the 19th
roll, you would have saved
money 322 times. If you took your bets off for 3 rolls after the 19th
roll you would have saved
money 322+ 264 + 226 , a total of 812 times.
If I'm figuring it right that is 1825 plus 1 roll
plus 1 roll plus 1 roll......that is 812 times
in 1828 rolls you would have saved money because you felt the 7 was
due and you took down your bets.

If my math is correct, do you not feel this is significant ?


I'm not a statistician, but I suspect than none of the variations you see
from the expected 16.67% are more than random noise. If I collect a
different set of 60,000 rolls, different length series will certainly be
slightly above over below the 16.67% from this set.

Attempting to deduce something from the variations in this data from the
expected value won't teach you anything; it's just the random noise in this
particular set of numbers. Obsevering that all of the series end with a 7
APPROXIMATELY 1/6th of the time is the real lesson.

--
Gregg C.


.

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