Re: Hardness tester wanted
- From: "Harold and Susan Vordos" <vordos@xxxxxxx>
- Date: Wed, 09 May 2007 07:57:30 GMT
"Sevenhundred Elves" <sevenhundred@xxxxxxxxxxxxx> wrote in message
news:kfd0i.40426$E02.16242@xxxxxxxxxxxxxxxxxx
Harold and Susan Vordos wrote:
<clutch@xxxxxxxxx> wrote in message
news:133jqh3hp6eh47c@xxxxxxxxxxxxxxxxxxxxx
"Tom Gardner" <tom(nospam)@ohiobrush.com> wrote:
Does anybody have a hardness tester laying around? Gunner has five or
six
I'd bet! (encased with rust maybe, but...)
Enco has a new one for 800 bucks iirc.
Wes
That's why I bought the old Wilson. They're quite proud of those things
when
they're new. I always wanted one, but couldn't justify the cost.
Getting one cheaply from ebay made it a reasonable acquisition. I
didn't
mind the rebuild, and had more than enough material on hand to make the
components. Truth be known, it was a fun job. I rarely comment on
machining being fun. The shine went off that for me years ago.
Harold
I have been thinking of making (or rather applying, for there is no
actual "making" involved) my own hardness tester for a cost of something
like zero.
This is how I figure:
IIRC, at least one of the different hardness tests is designed around
measuring the size of the impression made by a sphere, (help me with
their names please).
Instead of applying a precise force for a precise length of time, my
idea is that if I have a piece of steel with known hardness, and another
that is unknown, I put them both in a vise with a ball bearing between
them. Then squeeze hard. Now the pieces obviously get indented with the
same force and for the same length of time.
So I have get impressions, one in the unknown material, and one in the
known. Now I reason that the relative sizes of the impressions must
surely be proportional to the relative hardnesses of the materials.
Do you think this idea would work as I think it might? If it does, what
should I measure, the areas or the diameters of the circular indents?
S
In a sense, that's how a hardness tester works, but in the case of the
Wilson, it measures the depth of penetration, not the diameter.
Yeah, your idea would work, but I have serious doubts about the ability to
read the results and translate them to useful information with a reliable
degree of precision.
Harold
.
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