Re: rear rim seems to rub

In article <-d-dncHqcYZ9wd_anZ2dnUVZ_ournZ2d@xxxxxxxxxxxxx>,
jim beam <spamvortex@xxxxxxxxxxxxxxx> wrote:
Luns Tee wrote:
In article <r8ednVBcc51sj9zanZ2dnUVZ_j-dnZ2d@xxxxxxxxxxxxx>,
jim beam <spamvortex@xxxxxxxxxxxxxxx> wrote:
Yes, it is getting boring, however I repeat my question because
despite having been asked it over half a dozen times, you have yet
to give any sort of answer that is consistent with the fundamentals
of mechanics. A freely pivoting 1:1 lever has forces on its ends
in a 1:1 ratio, but you seem to believe that it can support a 2:1
ratio instead.
it's locked against the rim. it can therefore support the 2:1.

By your reasoning, if I place a 10kg weight on one side of a
beam balance (1:1 lever), and a 20kg weight on the other, the two are
able to balance in equilbrium because the scale is locked against 20kg
weight. Doesn't work that way.


no, you're actually arguing what i've said all along - that the
strongest force prevails. just like two 10kg weights and one lever arm
being twice as long as the other.

You clearly do not understand what it means for a force to
prevail. With a 10kg weight on one side and a 20kg weight on the other,
the scale does not just float balanced anyway, it tips towards the 20kg
side, and continues to tip until something changes to affect the
imbalance. When a scale tips over, it stops when the heavy-side pan hits
the table or encounters some other form of stop, and this stop provides
a 10kg upwards reaction to make up for the imbalance.
This stop is a third force, separate from the two that
constitute the imbalance, and it is this third force I've been looking
for in asking you how you think the Y arm can be in equilibrium. Every
answer you've given so far has related to either the cable or the pad,
and would only relate to what makes the 100N, 100N, or makes the 200N,
200N, but you claim that, hocus-pocus, the 2:1 ratio forms an equilbrium
anyway.

Despite your disbelief, the third force acting on the Y arm is
from the centering linkage, there being nothing else acting on the arm
after the cable and pad have been accounted for. However, the linkage
communicates with the C arm, and takes from the force at its pad as
much as it adds to the Y arm's. The net result is that the caliper's
mechanical advantage is the AVERAGE of its two arms', not one or the
other.

reason backwards: if lowest leverage ratio prevailed, the caliper would
have the same m.a. as single pivot - hopefully something you agree is
not the case.

Nobody has claimed anything about lowest ratio prevailing.

-Luns
.

Relevant Pages

  • Re: rear rim seems to rub
    ... jim beam wrote: ... side of the Y arm, vs. 200N on the pad side of the Y arm an equilibrium? ... lever can have forces on it in a 2:1 ratio yet be in equilbrium. ...
    (rec.bicycles.tech)
  • Re: rear rim seems to rub
    ... jim beam wrote: ... A freely pivoting 1:1 lever has forces on its ends ... in a 1:1 ratio, but you seem to believe that it can support a 2:1 ... beam balance, and a 20kg weight on the other, the two are ...
    (rec.bicycles.tech)
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