Re: rear rim seems to rub
- From: luns@xxxxxxxxxxxxxxxxxxxxxxx (Luns Tee)
- Date: Mon, 19 Nov 2007 04:11:23 +0000 (UTC)
In article <ArudnakJd_XLndzanZ2dnUVZ_t3inZ2d@xxxxxxxxxxxxx>,
jim beam <spamvortex@xxxxxxxxxxxxxxx> wrote:
Luns Tee wrote:
In article <vaidncGliJ07zKHanZ2dnUVZ_tyknZ2d@xxxxxxxxxxxxx>,
jim beam <spamvortex@xxxxxxxxxxxxxxx> wrote:
Luns Tee wrote:
In article <GOCdnY7kbLrAMaTanZ2dnUVZ_jmdnZ2d@xxxxxxxxxxxxx>,it can be compressed independently of the c-arm.
jim beam <spamvortex@xxxxxxxxxxxxxxx> wrote:
Luns Tee wrote:IF the y-arm is fixed, then I agree with the avid brake as a
In article <oZWdnS6ivZi-fKranZ2dnUVZ_jCdnZ2d@xxxxxxxxxxxxx>,but luns, with respect, if the y-arm is fixed, you have exactly the same
jim beam <spamvortex@xxxxxxxxxxxxxxx> wrote:
The one-side-fixed caliper is not a valid analogy: a 1:1 leverno, reconsider the avid disk caliper i mention. one pad is completelyFloating only means that the supposed 200N from the C arm padIf the ratio of the caliper as a whole is 2:1 as you say, the"floating" of the rim. just like in the avid mechanical disk brake caliper.
force being transmitted across the rim is 200N. How is 100N on the cable
side of the Y arm, vs. 200N on the pad side of the Y arm an equilibrium?
is carried through to the Y arm pad, but the question is of how the Y
arm is able to press 200N against this - this is implicit in the
question I pose. Repeating part of the question is not an answer to
the question. You still have not addressed the question of how a 1:1
lever can have forces on it in a 2:1 ratio yet be in equilbrium.
fixed, but braking force is applied equally from both pads because the
disk floats. rims do the same.
between the pad and cable clamp is not a fixed stop. If the Y arm were a
fixed stop, then it would not rotate on its pivot, and we're left with a
single-pivot brake. What is under discussion is dual-pivot brakes.
braking as with the avid disk brake.
model. However, you yourself have claimed that the Y arm is free to
pivot, independently of the C arm at that.
What makes the Y arm, thatapplication of pressure from the brake cable.
is otherwise free to pivot, into a fixed stop?
That is NOT a fixed stop.
it is relative to the rim. hence equilibrium is established.
A freely pivoting 1:1 lever transmits
force from the pad through to force at the cable in a 1:1 ratio. So I
ask you one more time, with 100N of cable tension, if things are as
you say, how does 200N at the pads constitute an equilibrium?
see above. re-read the posts of myself and joe riel - repetition is
getting boring.
Yes, it is getting boring, however I repeat my question because
despite having been asked it over half a dozen times, you have yet
to give any sort of answer that is consistent with the fundamentals
of mechanics. A freely pivoting 1:1 lever has forces on its ends
in a 1:1 ratio, but you seem to believe that it can support a 2:1
ratio instead. If you actually had a consistent picture of how the
calipier works, you could tell us what forces each arm experiences,
and also show that these forces agree with the fundamentals of
mechanics. Instead, you just offer a non-statement using the word
'equilibrium' as though it were synonymous with 'abracadabra'.
So far as Joe Riel's posts, I don't see how anything he's said
supports your assertions at all, nor do I imagine he appreciates your
trying to claim that they do, but I will let him speak for himself.
Believe what you want - at this point, I believe it's clear
to everybody else that you do not present a consistent story with
your claim of a 2:1 caliper ratio, nor of the centering linkage being
uninvolved.
-Luns
.
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