Re: I'd never seen this before

Tina <tbaker27705@xxxxxxxxx> wrote:
You are in error again.

The calculation would be based on a triangle, one length is earth
radius, the other, earth radius plus tower height. The third length is
the geometric distance from tower top to earth horizon.

Once again he is correct as far as he goes, but I doubt he really derived
the equations, otherwise he would be posting them just to prove how
clever he is.

So, before he has a chance to Google the answer:

Let the Earth be a billiard ball of radius R.

Let the height of an object be h.

Let the distance to the horizon be d.

Draw a circle.

Draw a radial line from the center to the circle.

At the intersection of the radial line and the circle, draw a line tangent
to the circle.

Draw another radial line and extend it until it intersects the tangent line.

The two radial lines and the tangent line form a right triangle, so:

sqrt (R^2 + d^2) = R + h

R^2 + d^2 = (R + h)^2

R^2 + d^2 = R^2 + 2Rh + h^2

d = sqrt (2RH + h^2)



--
Jim Pennino

Remove .spam.sux to reply.
.

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