Re: Mechanical destruction of electrons?
- From: throopw@xxxxxxxxx (Wayne Throop)
- Date: Mon, 17 Mar 2008 19:11:20 GMT
:: Of course, as in producing a neutron, the results in isolation will
:: spontaneously decay and produce an electron eventually....
: IsaacKuo <mechdan@xxxxxxxxx>
: How about electron capture (aka inverse beta decay)?
: http://en.wikipedia.org/wiki/Electron_capture
: So, a fully ionized Rubidium-83 nucleus could be strolling along and
: collide with your hapless electron, decaying into Krypton-83. Unlike
: a free neutron, this Krypton-83 nucleus is stable, so it won't just
: split out an electron a few minutes later.
That's one of the cases where it's not "in isolation". Another one,
with a somewhat larger nucleus stabilized with gravity instead of
the strong nuclear force, is a neutron star.
Also, I *think* you could add an electron and an antineutron and get
an antiproton (plus misc neutrino), which wouldn't decay in isolation.
I think. Isn't that one of the possibilities? Hm. Or does that imply
protons aren't necessarily stable? Hrm. Well, anyways, it ought to work.
I think.
"I think I am, therefore I am, I think." --- Pink Floyd
Wayne Throop throopw@xxxxxxxxx http://sheol.org/throopw
.
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