Re: Take One Magical Spacedrive
- From: Hop David <hopd@xxxxxxxxxxx>
- Date: Mon, 25 Jun 2007 08:48:44 -0700
sigidunum@xxxxxxxxx wrote:
On Jun 25, 9:24 am, Hop David <h...@xxxxxxxxxxx> wrote:
Well, according to http://www-ssg.sr.unh.edu/ism/what1.html
the interstellar medium has about 1 atom per cubic centimeter, 3 out of
4 atoms H, the 4th He.
It varies by about an order of magnitude, even in "normal"
interstellar space. So, in the immediate region of the Sun it's about
0.2 atoms/cc (because we're in the "local bubble").
To be honest, I have no idea how accurate the guestimate I cited is.
So each cubic centimeter would have 1.75 protons
or neutrons per cm^3 or about 3E-27 kg/cm^3
The cubic centimeters it'd pass through in a second would be velocity
(in cm/sec) * cross section of space craft (in cm^2)
I would guess kinetic energy is 1/2 * sqrt(1/(1-(v/c)^2)) * m * v^2.
A classical calculation gives a hydrogen atom at lightspeed a kinetic
energy of about 1.6E-27 kg * (3*10^8 m/s)^2 = ~1.4E-10 joules.
You're using E = mc^2 evidently. Which is probably right.
I was using KE = 1/2 mv^2
and multiplying mass by gamma to correct for relativistic speeds.
However at light speed gamma (sqrt(1/(1-(v/c)^2))) becomes
sqrt(1/0). This would give a hydrogen atom traveling at light speed infinite mass.
I recall making some progress trying to plow though special relativity. But that was a few years back. And I made no progress with general relativity. I used the words "I would guess . . ." because I'm not sure.
Two books to get my next trip to the city: A book on linear algebra (for another thread) and a book on relativity.
.
That's not much, but -- you're going to sweep through a lot of
hydrogen atoms as you zip along. You're moving at 30 billion
centimeters/second. So, 3 x 10^10 impacts/second gives a power input
of 4.2 watts/square centimeter, or 42,000 watts/square meter.
If that's right, then the leading edge of your ship is going to glow.
Brightly.
Relativistic correction: if you're traveling at 0.99c, then the
classical calculation drops the power output by 0.99^3 (because the
kinetic energy drops as the square of the velocity, and the collisions/
second drop too). But the atoms will seem to be about 7 times as
massive, and so will produce 7 times as much energy. Yikes.
Note that dropping your speed a little helps a lot. At 0.9c the power
input is down to about 3 watts/cm^2, even with relativity. At 0.5c
it's a mere ~half-watt/cm^2.
That still seems high, so I'd be happy if someone checked my
calculations.
Doug M.
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