Re: Tracking
- From: Erik Max Francis <max@xxxxxxxxxxx>
- Date: Sat, 29 Apr 2006 13:39:07 -0700
Wayne Throop wrote:
What is emitting it *does* make a difference in how much energy the photon has. And its wavelength. Otherwise, there wouldn't
be relativistic doppler shift.
Sure. What I was disputing was that implication (apparently unintended by his later responses) that photons emitted by a particle travelling faster-than-light would somehow travel faster than light themselves, which is nonsensical.
Once you are going FTL in a naive sense (ie, without wormholes or
warp bubbles or any such), wavelength becomes imaginary when you
apply relativistic doppler to objects moving at FTL velocities.
I still don't follow where this imaginary photon wavelength is coming from. When the photon is emitted it travels at c. It never travels at any other speed. If it has finite energy when it is emitted, it has finite wavelength (or frequency). Where is the imaginary wavelength supposed to becoming from? It still sounds like people are still using the model where the photon "starts out" travelling faster than light. But that very explicitly never happens since photons are luxons and luxons always travel at c.
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