Re: Second TI-Nspire report

Hi,

Mathematica gives the following symbolic answer including sqrts:
http://www.noemanetz.de/bilder/Nspire/matrixform_inverse.gif


Hi,

It is indeed not simplified.
Checking that A*inv(A)=id is probably not a good
way to test the sqrt simplifications algorithms
of mathematica, since using their inverse this
can be checked using only rational simplification
(i.e. replace sqrt by unknowns, without using
sqrt(x)^2=x). It would require some identities
involving sqrt.
.

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