Re: Void function returns value

En news:fgaann$ut9$1@xxxxxxxx, Philip Potter va escriure:
Antoine Leca wrote:
void foo() {;}
int main() {
void *k;
k = foo;
The type of foo is [...] void(*)(void),

I believe there are no prototype in scope, so I think the type of
foo is rather void(*)().

Is that a distinct type?

My reading of 6.7.5.3p15 is that they are different, but compatible.

In both cases foo is declared as taking no arguments.

I read http://www.open-std.org/jtc1/sc22/wg14/www/docs/dr_317.htm as saying
that

void foo() {}

is also compatible with

void g(){ if(0) foo(1); }

While I know that

void foo(void);
void g(){ if(0) foo(1); }

should be diagnosed.


But I can easily be wrong on this one, so please check the holy words from
the knowledgeable people (there was a recent thread about this, subject was
"Prototype or not prototype?")


Antoine

.

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