Re: rotate image around all axes

ImageAnalyst <imageanalyst@xxxxxxxxxxxxxx> wrote in message <df31a29f-0103-4c3a-b199-dbcd72196fb3@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>...
On Nov 26, 8:25=A0pm, "benjamin m?ller" <pern...@xxxxxxx> wrote:
hi,

at first sorry if my english is not perfect. I got pictures of an object =
taken from a camera which angle is not normal to the object plane. I got th=
e angles to rotate the image around the x,y and z axes. For that purpose i =
thought i can use maketform and imtransform. Now i got 2 problems. The rota=
tion of the Image around the Z axes works good with following rotation matr=
ix:

T =3D [cosd(angle) -sind(angle) 0; sind(angle) cosd(angle) 0;0 0 1];

Problem 1:
when i try the same with the x and y axes with the following matrixs

T =3D [1 0 0; 0 cosd(angle) -sind(angle);0 sind(angle) cosd(angle)], %x-a=
xes
T =3D [cosd(angle) 0 sind(angle); 0 1 0;-sind(angle) 0 cosd(angle)], %y-a=
xes

it works too, but the result is not right. when im trying to rotate with =
0.5 degrees the result looks like it has been rotated with more than 45 deg=
rees.

Problem2:
I want the pictures to look like there were taken from a camera which ang=
le is normal to the image plane, but for this purpose I need the axes which=
i want to rotate around in the middle of the picture. Got anybody an idea =
how to realize that?

thank you very, very much for answering!!

at last: for testing i used following code:

I=3Dimread('testpic.jpg');
angle=3D0.05;

figure;
imshow(I)

% T =3D [1 0 0; 0 cosd(angle) -sind(angle);0 sind(angle) cosd(angle)], %x
=A0T =3D [cosd(angle) 0 sind(angle); 0 1 0;-sind(angle) 0 cosd(angle)], %=
y
% T =3D [cosd(angle) -sind(angle) 0; sind(angle) cosd(angle) 0;0 0 1], %z

t_proj =3D maketform('projective',T);
I_projective =3D imtrangleform(I,t_proj);
figure;
imshow(I_projective);

-----------------------------------
benjamin:
For problem #1, are you sure you're passing in radians? Sin and cos
want radians so if you pass in 0.5 you're not passing in half a degree
but .5 radians which would be around 30 degrees.
Regards,
ImageAnalyst

hello imageanalyst,

thanks for your answer! I used sind and cosd so i can give the arguments in degrees...so that shouldnt be the problem:/ thank you anyway:)

regards,
benjamin
.

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