Re: simple array manipulation without loops?

Why is Desired the desired ordering, and not Desired2 =
[1; 3; 9; 2; 4]?
Since 3 appears first in A, shouldn't it be before the
elements of B in the
Desired array?

Am I reading too much into "maintain the ordering"?


The output being [1; 9; 2; 3; 4] instead of [1; 3; 9; 2; 4]
is merely an artifact of the order the arguments are passed
to the "unique" function (ie for repeated values the last
occurance has it's indicie passed)

A = [1; 3; 9];
B = [2; 3; 4];
temp=[A; B];**
[r,m,n]=unique(temp);
Desired = temp(sort(m))
EQUALS[1; 9; 2; 3; 4]

Where as
A = [1; 3; 9];
B = [2; 3; 4];
temp=[B; A];**
[r,m,n]=unique(temp);
Desired = temp(sort(m))
EQUALS[2; 4; 1; 3; 9]

******

For my purpose, i must have at least one array maintain its
original order, however, i can achieve this by just making
that array the second argument in the stacking line temp=
[X,X].

.

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