Re: Question about Integral Evaluation

Hi and thank you for your answers.

The fact is the function I have to evaluate is part of the
code (I have just copy a part of the code here); so is
there a method to incorporate the integral calculation
within it?

The variable used for integration is xVct. Sorry, forgot
to mention it...

Concerning the choice of variables, I'm just pursuing the
work of a previous student so, according to my teacher, I
have to respect his notations.

Best Regards





"tin julien" <tnj@xxxxxxxxxxxxxxxx> wrote in message
<g2e4o1$ppr$1@xxxxxxxxxxxxxxxxxx>...
Hi everybody,
Can someone help me to solve this problem ?

I have to evaluate the integral of this function
(FunctDenom) between 0.01 and 1.0501
I try several instructions including int but it says
that
it doesn&#8217;t take double in account.
I also tried quad but I don&#8217;t know how to set the
function
accordingly to the need of the program.
Thanks by advance.
Best Regards


Here is the code:

Rg= 1000;


Stp= 0.05;
TestDstVct= Rg*[Stp:Stp:1.1]



xVct = TestDstVct/RadiusC;


GammaOdB= 10*log10(...
AaCorrected*...
(Alpha - 2)*...
(((2./xVct) - 1).^Alpha)./...
((2 - xVct).^2));
GammaOlin=10.^(GammaOdB./10);



CapacityO=log2(1+GammaOlin);

FunctDenom=1./CapacityO;




.

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