Re: pipe question

On Tue, Apr 5, 2011 at 4:35 PM, Chad Perrin <code@xxxxxxxxxxxx> wrote:
On Tue, Apr 05, 2011 at 12:30:47PM +0900, Josh Cheek wrote:
On Mon, Apr 4, 2011 at 7:12 PM, 7stud -- <bbxx789_05ss@xxxxxxxxx>
wrote:

Here is an example that might prove illustrative:

if 1 > 10
 x = 'hello'  #never executes
end

puts x  #=> nil
puts y  #=> undefined local variable or method `y'
       #for main:Object (NameError)

Good thought. I'm honestly surprised that works! I guess it must add x
to the symbol table at parse time.

Is that something we should be able to depend on, though -- or just an
accident of implementation?

I think it's a language feature. From the line where an assignment to
a identifier is found this identifier denotes a local variable -
whether the code is actually executed does not matter. This is only
about syntactical order. Consider

$ ruby19 -e 'puts(x) if x=1'
-e:1: warning: found = in conditional, should be ==
-e:1:in `<main>': undefined local variable or method `x' for
main:Object (NameError)
$ ruby19 -e 'x=1;puts(x) if x'
1
$

Kind regards

robert

--
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/

.

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