Efficient file downloading
- From: Kyle Hunter <keletmaster@xxxxxxxxx>
- Date: Thu, 21 Feb 2008 20:54:36 -0500
Hello,
I'm using open-uri to download files using a buffer. It seems very
inefficient in terms of resource usage (CPU is ~10-20% in usage).
If possible, I'd like some suggestions for downloading a file which
names the outputted file the same as the URL, and does not actually
write if the file comes out to a 404 (or some other exception hits).
Current code:
BUFFER_SIZE=4096
def download(url)
from = open(url)
if (buffer = from.read(BUFFER_SIZE))
puts "Downloading #{url}"
File.open(url.split('/').last, 'wb') do |file|
begin
file.write(buffer)
end while (buffer = from.read(BUFFER_SIZE))
end
end
end
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