Re: extracting numbers from a string

If you just want to extract one number from a string, you could write
something like :

if a="DSC_1234.jpg"

then a[/\d+/] will give you the first longest string of numbers, so
1234.

If you want to be more precise, you could use parenthesis to extract
the exact portion you want, like :

a[/DSC_(\d+)\.jpg/,1] (<=> a.match(/DSC_(\d+)\.jpg/)[1])

or even : a[/\ADSC_(\d+)\.jpg\Z/,1]




On 12 juin, 08:45, Matt Jones <mattjonesph...@xxxxxxxxx> wrote:
I have filenames from various digital cameras: DSC_1234.jpg,
CRW1234.jpg, etc. What I really want is the numeric portion of that
filename. How would I extract just that portion?

I expect it to involve the regex /\d+/, but I'm unclear how to extract a
portion of a string matching a regex.

Thank you

--
Posted viahttp://www.ruby-forum.com/.


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