Re: Integer to byte string - Speed improvements
- From: "Rick DeNatale" <rick.denatale@xxxxxxxxx>
- Date: Fri, 1 Sep 2006 04:08:32 +0900
On 8/31/06, Phrogz <gavin@xxxxxxxxxxxx> wrote:
I'm writing code that needs to store an integer as a sequence of bytes.
Array#pack works for 1-, 2-, and 4-byte integers, but I want to be able
to support Bignums as well.
I have working code below. I'm happy with it. However, I thought I'd
pose the question to the list: how much faster can you make the below
code run?
# The natural log of 2 (for base-2 logarithms)
Math::LOG2 = Math.log( 2 )
No need for these, I'm on a campaign to let integers be integers.
class Integer
# Converts the integer into a string, where the value of each
character
# is a byte in the bit representation of the integer.
# Low-order bytes appear first in the string.
#
# If the number of characters is not specified, the fewest number of
# characters that can represent the integer is used.
#
#
def to_bytestring( num_chars=nil )
replace these four lines:
unless num_chars
bits_needed = Math.log( self ) / Math::LOG2
By the way, this won't work for negative integers. Dealing with
negative numbers provides some interesting questions which I'll ignore
for now.
num_chars = ( bits_needed / 8.0 ).ceil
end
with
raise RangeError.new("Can't convert negative integer to bytestring")
num_chars ||= self.size
if pack_code = { 1=>'C', 2=>'S', 4=>'L' }[ num_chars ]I might try getting rid of the multiplication
[ self ].pack( pack_code )
else
(0...(num_chars)).map{ |i|
(( self >> i*8 ) & 0xFF ).chr
}.join
end
With something like:
result = []
i = self
until i == 0
result << (i & 0xFF).chr
i >>= 8
end
So following those ideas:
rick@frodo:/public/rubyscripts$ cat tobytes.rb
class Integer
def to_bytestring(num_chars=nil)
raise RangeError.new("Can't convert negative number to
bytestring") if self < 0
num_chars ||= self.size
mask = 0xFF << (8 * num_chars - 1)
while (self & mask) == 0
mask >>= 8
num_chars -= 1
end
result = []
bits_left = self
until bits_left == 0
result << (bits_left & 0xFF).chr
bits_left >>= 8
end
result.join
end
# Creates an integer from a byte string.
# See Integer#to_bytestring for more information.
def self.from_bytestring( str )
val = 0
index = 0
str.each_byte{ |b|
val += b << 8 * index
index += 1
}
val
end
end
[
0x48,
0x6948,
0x646c726f57206f6c6c6548,
0x217962755220666f207463657073612074656577732061207369206d756e676942
].each{ |i| puts i, i.to_bytestring, '' }
rick@frodo:/public/rubyscripts$ ruby tobytes.rb
72
H
26952
Hi
121404708493354166158910792
Hello World
3876042760240808297111079005855559646422331404814505579794973210389374306838850
Bignum is a sweet aspect of Ruby!
--
Rick DeNatale
My blog on Ruby
http://talklikeaduck.denhaven2.com/
.
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- Integer to byte string - Speed improvements
- From: Phrogz
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