Re: Regular expression help for 12 hour clock?
- From: "Evertjan." <exjxw.hannivoort@xxxxxxxxxxxx>
- Date: 07 Jul 2008 10:54:45 GMT
SAM wrote on 07 jul 2008 in comp.lang.javascript:
Evertjan. a écrit :
mw wrote on 06 jul 2008 in comp.lang.javascript:
Hey, thanks everyone for their posts! I used a bit from both andvar regexmatch = /^(1[012]|[1-9]):[0-5]\d\s[ap]\.m\.$/i;
rated both highly in google groups. (for whatever that is worth)
It seems to be working quite well for me now! The final code I used
is a bit of a regex from my post, and both of the above posts.
The code I'm using now(which has some ()'s still because I decided I
may actually use them later for remembering the text) is
var regexmatch = /(^1[012]:[0-5][0-9]|^[1-9]:[0-5][0-9])\s[ap]\.m\./
i;
var regexmatch = /^(1[012]|[1-9]):[0-5]\d\s[ap]\.?m\.?$/i;
The implied using of .match() can better be exchanged for .test(), so
var regextest = /^(1[012]|[1-9]):[0-5]\d\s[ap]\.?m\.?$/i;
The whole idea of using am/pm is wrong,
it leads to misakes outside strict local area's, so use:
var testResult = false;
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)
.
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- From: mw
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