Re: Solution for Floating-Point Errors

David Mark said the following on 7/23/2007 5:28 PM:
On Jul 23, 4:35 pm, vunet...@xxxxxxxxx wrote:
Is there a good solution for floating-point errors?
If I got:
0.00831 + 0.000001 = 0.00831109999999999999
can I avoid this by a better method than comparing 2 number length
after decimal point and using toFixed() to match shorter number with
another one?
Thanks.

Yes. To make it simpler, multiply each by 1000000 before adding:

8310 + 1 = 8311


0.00831 + 0.000001 != 8311

--
Randy
Chance Favors The Prepared Mind
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