Re: how is Haskell not robust?
- From: raould <raould@xxxxxxxxx>
- Date: Thu, 4 Jun 2009 14:51:35 -0700 (PDT)
Although you have to learn semantics first in Haskell to predict its
memory behaviour, the code produces correct results in most cases, even
if you're leaking space. Bugs are very rare.
thanks to all for the thoughts about this subject.
i think i get it that laziness can lead to big space usage. and i
guess there is some debate about how easy it is for programmers to see
"oh this code right here could lead to a space leak!"
so, how could/do people see that something could be a space leak? is
there anything about it that could be automated?
thanks.
.
- Follow-Ups:
- Re: how is Haskell not robust?
- From: Dirk Thierbach
- Re: how is Haskell not robust?
- From: Jon Harrop
- Re: how is Haskell not robust?
- From: raould
- Re: how is Haskell not robust?
- References:
- Re: how is Haskell not robust?
- From: Adrian Hey
- Re: how is Haskell not robust?
- From: Ertugrul Söylemez
- Re: how is Haskell not robust?
- From: Adrian Hey
- Re: how is Haskell not robust?
- From: Ertugrul Söylemez
- Re: how is Haskell not robust?
- From: Adrian Hey
- Re: how is Haskell not robust?
- From: Ertugrul Söylemez
- Re: how is Haskell not robust?
- From: Jon Harrop
- Re: how is Haskell not robust?
- From: Ertugrul Söylemez
- Re: how is Haskell not robust?
- From: Jon Harrop
- Re: how is Haskell not robust?
- From: Ertugrul Söylemez
- Re: how is Haskell not robust?
- Prev by Date: Re: State monads in F#
- Next by Date: Re: how is Haskell not robust?
- Previous by thread: Re: how is Haskell not robust?
- Next by thread: Re: how is Haskell not robust?
- Index(es):