Re: char** function parameters

> Suppose I have the following function:
>
> void doSomething(char** array, int size);
>
> Normally, I would call the function with an array of, say, 3
> elements...
>
> char* strs[] = { "str1","str2","str3" };
> doSomething(strs, 3);

what this declaring is a pointer to an arrray. an array in memory is a
pointer to the data(i.e pointer to a pointer). The doSomething is asking for
a ponter to a pointer. which is way this one works

>
> That works fine. But if I want to pass it only one string, I would
> think this would work....
>
> char* str = "str1";
> doSomething(&str, 1);

while this declares a pointer to the data, doSomething is expecting a
pointer to a pointer and so it is treating "Str1" as the memory adress (i.e.
it is going to goto to adress 0x53747231) which is not where the string is.

>
> It compiles with a warning about incompatible pointer types, and
> needless to say it doesn't behave as I expected. "str1" does not get
> passed into the function. What am I doing wrong? Or is it simply not
> possible to pass a single char* into this function?
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